Kenmore 9890, 46-9890, 4609890000 and 469890 Compatible Filter
Sears Kenmore 9890, 46-9890, 4609890000 and 469890 Compatible Replacement Refrigerator Water Filter Cartridge
- One Sears Kemore / LG Replacement Fridge Water Filter Cartridge by KleenWater
- Advanced Carbon Block Technology Provides the Very Best Water Filtration
- Replaces:Kenmore 9890, 46-9890, 4609890000 and 469890
- Replaces: LG LT500P, 5231JA2002A, 5231JA2002A-S, 5321JA2002, 5231JA2002B-S and 5231JA2002B
The KW6005A refrigerator filter is for use with Sears Kenmore 9890, 46-9890, 4609890000 and 469890
LG LT500P, 5231JA2002A, 5231JA2002A-S, 5321JA2002, 5231JA2002B-S, 5231JA2002B, Supco WF-290, WF290 and WaterSentinel WSL-1. Made in the USA.
ADVANCED FILTRATION TECHNOLOGY. This KleenWater/EcoAqua refrigerator water filter contains a compressed carbon block which provides tremendous capacity to remove and/or reduce impurities and sediment that may be present in your refrigerator drinking water. This carbon block water filter has millions of adsorptive sites on its surface and within the structure. Adsorption is the capability of all solid substances to attract to their surfaces molecules with which they are in contact. This carbon block water filter cartridge can remove/reduce chlorine, volatile organic compounds and other contaminants that affect taste and odor. These processes ensure that you are getting the cleanest and best tasting water possible. FILTER FEATURES: Provide cleaner, fresher water by reducing impurities. Made in America. KleenWater is a trademark of Pavel Water Filtration.
FREE shipping on every order - U.S.A. Shipping Only
Our KleenWater brand of refrigerator water filters are high quality replacement cartridges which meet or exceed original filter performance and specifications. We ship within the Contiguous United States plus Alaska and Hawaii. Most items ship within 24 hours. We guarantee that the product will arrive in good condition or you may return the product for a full refund. Call us at 877-553-3698 and we will be happy to answer any questions.